Mongo查询语句方法与sql 对比

2013 年 11 月 18 日 at 下午 8:13分类:Mysql

有好多人是过sql之后 再用mongo 很不习惯它的查询方式，下面是查询语句与sql的对比。

SQL Statement Mongo Query Language Statement
CREATE TABLE USERS (a Number, b Number) Implicit or use MongoDB::createCollection().
INSERT INTO USERS VALUES(1,1) $db->users->insert(array(“a” => 1, “b” => 1));
SELECT a,b FROM users $db->users->find(array(), array(“a” => 1, “b” => 1));
SELECT * FROM users WHERE age=33 $db->users->find(array(“age” => 33));
SELECT a,b FROM users WHERE age=33 $db->users->find(array(“age” => 33), array(“a” => 1, “b” => 1));
SELECT a,b FROM users WHERE age=33 ORDER BY name $db->users->find(array(“age” => 33), array(“a” => 1, “b” => 1))->sort(array(“name” => 1));
SELECT * FROM users WHERE age>33 $db->users->find(array(“age” => array(‘$gt’ => 33)));
SELECT * FROM users WHERE age<33 $db->users->find(array(“age” => array(‘$lt’ => 33)));
SELECT * FROM users WHERE name LIKE “%Joe%” $db->users->find(array(“name” => new MongoRegex(“/Joe/”)));
SELECT * FROM users WHERE name LIKE “Joe%” $db->users->find(array(“name” => new MongoRegex(“/^Joe/”)));
SELECT * FROM users WHERE age>33 AND age<=40 $db->users->find(array(“age” => array(‘$gt’ => 33, ‘$lte’ => 40)));
SELECT * FROM users ORDER BY name DESC $db->users->find()->sort(array(“name” => -1));
CREATE INDEX myindexname ON users(name) $db->users->ensureIndex(array(“name” => 1));
CREATE INDEX myindexname ON users(name,ts DESC) $db->users->ensureIndex(array(“name” => 1, “ts” => -1));
SELECT * FROM users WHERE a=1 and b=’q’ $db->users->find(array(“a” => 1, “b” => “q”));
SELECT * FROM users LIMIT 20, 10 $db->users->find()->limit(10)->skip(20);
SELECT * FROM users WHERE a=1 or b=2 $db->users->find(array(‘$or’ => array(array(“a” => 1), array(“b” => 2))));
SELECT * FROM users LIMIT 1 $db->users->find()->limit(1);
EXPLAIN SELECT * FROM users WHERE z=3 $db->users->find(array(“z” => 3))->explain()
SELECT DISTINCT last_name FROM users $db->command(array(“distinct” => “users”, “key” => “last_name”));
SELECT COUNT(*y) FROM users $db->users->count();
SELECT COUNT(*y) FROM users where AGE > 30 $db->users->find(array(“age” => array(‘$gt’ => 30)))->count();
SELECT COUNT(AGE) from users $db->users->find(array(“age” => array(‘$exists’ => true)))->count();
UPDATE users SET a=1 WHERE b=’q’ $db->users->update(array(“b” => “q”), array(‘$set’ => array(“a” => 1)));
UPDATE users SET a=a+2 WHERE b=’q’ $db->users->update(array(“b” => “q”), array(‘$inc’ => array(“a” => 2)));
DELETE FROM users WHERE z=”abc” $db->users->remove(array(“z” => “abc”));